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21 April, 00:20

What is the volume of 0.120 g of C2H2F4

vapor at 0.970 atm and 22.4°C?

Answer in units of L.

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Answers (1)
  1. 21 April, 00:40
    0
    V = 0.031L

    Explanation:

    P = 0.97atm, V=?, n = 0.12/98 = 0.00122mol, R = 0.082, T = 22.4+273 = 295.4

    Applying

    PV=nRT

    0.970*V = 0.00122*0.082*295.4

    Simplify the above equation

    V = 0.031L
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