How many moles of gas will occupy a volume of 0.53 L at a temperature of 329 K and pressure of 3.0 atm? n = ... mol

You have to rewrite the ideal gas law in terms of n. (n=PV/RT)

you are given V=0.53L, T=329K, and P=3.0atm, R is a constant so you already know that R=0.08206atmL/molK.

n = (3.0atmx0.53L) / (0.08206atmL/molKx329K)

n=0.0589mol gas