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15 April, 11:01

4. If an experimental value for a given observation was 415 nm while the theoretical value

was 435.8 nm, what is the percent error of the observation?

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Answers (1)
  1. 15 April, 11:10
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    Answer: % error of observation is 4.77%

    Explanation:

    Given:

    Observation value = 415nm

    theoretical value = 435.8nm

    Percent error of observation = theoretical value - observation value / theoretical value x 100 %

    = 435.8-415/435.8 = 0.04772 x 100 = 4.77%

    therefore % error of observation is 4.77%
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