Ask Question
25 September, 06:23

The average time it takes for a molecule to diffuse a distance of x cm is given by t=x^2/2D where t is the time in seconds and D is the diffusion coefficient. Given that the diffusion coefficient of glucose is 5.7 x 10^-7 cm2/s, calculate the time it would take for a glucose molecule to diffuse 10 pm, which is roughly the size of a cell.

+3
Answers (1)
  1. 25 September, 06:43
    0
    time to diffuse x cm is given by the relation

    t = X² / 2D

    D = 5.7 x 10⁻⁷

    t = X² / 2 x 5.7 x 10⁻⁷ = X² x 10⁷ / 11.4 s

    X = 10 pm = 10 x 10⁻¹² m = 10 x 10⁻¹⁰ cm = 10⁻⁹ cm

    t = (10 ⁻⁹) ² x 10⁷ / 11.4 = 10⁻¹¹ / 11.4 = 8.77 x 10⁻¹³ s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The average time it takes for a molecule to diffuse a distance of x cm is given by t=x^2/2D where t is the time in seconds and D is the ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers