assuming gasoline can be represented as C8H18, how much oxygen is needed to completely burn this fuel. answer in grams of oxygen per gram of gasoline

3.51 g of oxygen per gram of gasoline is required.

Explanation:

Solution:

First of all we will write the balance chemical equation.

C8H18 + 12.5O2 → 8CO2 + 9H2O

This equation shows that,

1 mole of gasoline react with 12.5 mole of oxygen for complete burning.

mass of one mole of gasoline = 8*12 + 18*1 = 114 g

mass of 12.5 mole of oxygen = 12.5 (16*2) = 400 g

Formula:

mass of oxygen per gram of gasoline = (400 / 114) = 3.51

so, 3.51 g of oxygen require for per gram of gasoline.