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31 July, 11:37

How many moles of KBr are present in 8.96 x 10^21

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  1. 31 July, 11:53
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    0.015 moles

    Explanation:

    One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 * 10^23. That is, 1 mole of a compound will have 6.022 * 10^23 molecules.

    In our case, We are given 8.96 x 10^21 molecules of KBr

    We need to find the number of moles in 8.96 x 10^21 molecules

    1 mole of KBr = 6.022 * 10^23 molecules.

    8.96 x 10^21 molecules = ?

    Therefore;

    (1 * 8.96 x 10^21 molecules) : 6.022 * 10^23 molecules.

    = 1.488 * 10^-2 moles

    = 0.01488 moles

    = 0.015 moles
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