Calculate the solubility of barium carbonate, baco3, in pure water (ksp = 2.0  10-9 for baco3).

Answer is: molar solubility of barium carbonate is 4.47·10⁻⁵ M.

Chemical reaction:BaCO₃ (s) → Ba²⁺ (aq) + CO₃²⁻ (aq).

Ksp = 2.0·10⁻⁹.

s (BaCO₃) = ? M.

s (BaCO₃) = s (Ba²⁺) = s (CO₃²⁻) = x.

Ksp = s (Ba²⁺) · s (CO₃²⁻).

Ksp = x · x.

2.0·10⁻⁹ = x².

x = √2.0·10⁻⁹ = 4.47·10⁻⁵ M.