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1 January, 05:04

For a given sample of ch3oh, the enthalpy change during the reaction is 82.3 kj. how many grams of methane gas are produced?

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  1. 1 January, 05:34
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    The equation is as follows;

    2CH3OH (g) = 2CH4 (g) + O2 (g), ΔH = + 252.8 kJ

    From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.

    Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2*82.3) / 252.3

    = 0.6524 moles

    which is equivalent to 0.6524 * 16 = 10.438 g

    There, the mass of CH4 produced will be 10.438 g
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