Ask Question
28 September, 04:39

rinking water suggest an upper limit of 250 mg/L for chloride ion. If 1.03*104 liters of water in a storage tank contains 1.40 grams of Cl-, what is the contaminant level in ppm? in ppb? Is this level acceptable based on EPA guidelines?

+5
Answers (1)
  1. 28 September, 04:59
    0
    This water has a level acceptable, 0.1359ppm and 135.9ppb.

    Explanation:

    1.40g of Cl⁻ are:

    1.40g Cl⁻ * (1000mg / 1g) = 1400mg Cl⁻

    In 1.03x10⁴L:

    1400mg / 1.03x10⁴L = 0.1359mg/L.

    As the upper limit of Cl⁻ in water is 250mg/L, this water has a level acceptable

    ppm are the ratio between mg of solute and liters of solution, that means the tank contains 0.1359mg/L = 0.1359ppm

    ppb, parts per billion are 1000 times ppm, thus, parts per billion of the storage tank are:

    0.1359ppm * 1000 = 135.9ppb
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “rinking water suggest an upper limit of 250 mg/L for chloride ion. If 1.03*104 liters of water in a storage tank contains 1.40 grams of ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers