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18 June, 12:17

For the Reaction represented by the equation below what mass of product will form if 34.6 moles of sodium react with excess chlorine gas

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  1. 18 June, 12:32
    0
    2024.1g

    Explanation:

    Given parameters:

    Number of moles of Na = 34.6moles

    Unknown:

    Mass of product formed = ?

    Solution:

    We must first establish the reaction equation as shown below;

    2Na + Cl₂ → 2NaCl

    We solve from the known to the unknown specie;

    2 moles of Na produced 2 moles of NaCl

    34.6moles of Na will produce 34.6moles of NaCl

    Now to find the mass of NaCl;

    mass = number of moles x molar mass = 34.6 x (23 + 35.5) = 2024.1g
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