A carbon forms two bonds to two X atoms plus two more bonds to two hydrogen atoms. If the hybridization to each X has 79.7% p-character, what is the X-C-X bond angle in degrees to the nearest tenth of a degree? Hint: recall our discussion of Bent's rule and Coulson's directionality theorem.

Question

Rudy Ali

Chemistry

4 March, 16:44

A carbon forms two bonds to two X atoms plus two more bonds to two hydrogen atoms. If the hybridization to each X has 79.7% p-character, what is the X-C-X bond angle in degrees to the nearest tenth of a degree? Hint: recall our discussion of Bent's rule and Coulson's directionality theorem.

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Emery · Answer 1

The bond angle is equal to 104.8°

Explanation:

With the Bent's rule, smaller bonds are formed between the ligands of the electronegative element, therefore, we have to:

cosθ = (p-1) / p, where p = 79.7% = 0.797

Replacing:

cosθ = (0.797-1) / 0.797

θ = cos^-1 (-0.254) = 104.8°