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12 June, 03:55

7.5 g of aluminum reacts with an excess of oxygen how many grams of aluminum oxide are produced?

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  1. 12 June, 04:03
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    14.2 grams

    Let's start by looking up the atomic weights of aluminum and oxygen. Atomic weight aluminum = 26.981539

    Atomic weight oxygen = 15.999

    Moles Al = 7.5 g / 26.981539 g/mol = 0.277967836

    The formula for aluminum oxide is Al2O3, so for every 2 moles of Al, 3 moles of O is required. So let's calculate the number of moles of O we need and from that the mass.

    0.277967836 mol / 2 * 3 = 0.416951754 mol

    Mass O2 = 0.416951754 * 15.999 = 6.670811105

    The mass of aluminum oxide is simply the mass of aluminum plus the mass of oxygen. So:

    7.5 g + 6.670811105 g = 14.17081111 g

    Rounding to 1 decimal place gives 14.2 g.
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