2 A (g) + B (g) / longrightarrow⟶ 2 C (g)

Rate = k [A][B]

At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The observed rate for the formation of C is 0.36 mol L-1 sec-1.

The numerical value of k, the rate constant, is closest to

108

0.040

0.12

6.0

Question

Bonnie

Chemistry

17 January, 22:33

2 A (g) + B (g) / longrightarrow⟶ 2 C (g)

Rate = k [A][B]

At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The observed rate for the formation of C is 0.36 mol L-1 sec-1.

The numerical value of k, the rate constant, is closest to

108

0.040

0.12

6.0

+5

Answers (1)

Know the Answer?

Brynlee Erickson · Answer 1

The correct answer is 0.12.

Explanation:

According the reaction kinetics we all know that

Rate=k[A][B]

K = rate constant

[A] = Concentration of A

[B] = Concentration of B

R=0.36mol/litre/sec

K=?

K = rate:[A][B]

= 0.36:3

=0.12

2 A (g) + B (g) / longrightarrow⟶ 2 C (g)Rate = k [A][B]At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The observed rate for the formation of C is 0.36 mol L-1 sec-1.The numerical value of k, the rate constant, is closest to1080.0400.126.0

2 A (g) + B (g) / longrightarrow⟶ 2 C (g)

Rate = k [A][B]

At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The observed rate for the formation of C is 0.36 mol L-1 sec-1.

The numerical value of k, the rate constant, is closest to

108

0.040

0.12

6.0