An excess of Ba (No3) 2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4. determine The concentration in moles per litre of the Ba (No3) 2 solution?

Question

Aimee Benjamin

Chemistry

14 March, 13:38

An excess of Ba (No3) 2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4. determine The concentration in moles per litre of the Ba (No3) 2 solution?

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Michelle Moore · Answer 1

Chemical reaction: Ba (NO₃) ₂ + H₂SO₄ → BaSO₄ + 2HNO₃.

V (H₂SO₄) = 250 mL : 1000 mL/L = 0,25 L.

m (BaSO₄) = 0,55 g.

n (BaSO₄) = m (BaSO₄) : M (BaSO₄).

n (BaSO₄) = 0,55 g : 233,38 g/mol.

n (BaSO₄) = 0,00235 mol.

From chemical reaction: n (BaSO₄) : n (Ba (NO₃) ₂) = 1 : 1.

n (Ba (NO₃) ₂) = 0,00235 mol.

c (Ba (NO₃) ₂) = n (Ba (NO₃) ₂) : V.

c (Ba (NO₃) ₂) = 0,00235 mol : 0,25 L.

c (Ba (NO₃) ₂) = 0,0095 mol/L.