Determine the volume occupied by 0.582 mol of a gas at 15 degrees Celsius if the pressure is 81.8 KPA?

Ideal gas law:

PV=nRT ⇒V = (nRT) / P

P=pressure

V=volume

n=number of moles

R=gas constant = 0.082 atm. litres/ºK mol

T=temperature

P=81.8 Kpa * (1 atm / 101.325 Kpa) ≈0.81 atm.

n=0.582 moles

T=15+273.15=288.15ºK

R=0.082 atm. litres/ªKmol

V = (0.582 moles*0.082 atm l/ºKmol * 288.15ºK) / 0.81 atm≈17.04 litres.

Sol: 17.04 litres.