At 40°c, the ion-product constant of water, kw, is 2.88*10-14. what is the ph of pure water at 40°c?

Question

Nikita

Chemistry

27 November, 19:01

At 40°c, the ion-product constant of water, kw, is 2.88*10-14. what is the ph of pure water at 40°c?

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Answers (1)

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Jayden Simon · Answer 1

Answer is: pH value of pure water at 40°C is 6.77.

Kw = 2.88 ·10⁻¹⁴.

Kw = [H⁺] · [OH⁻].

[H⁺] = [OH⁻] = x.

Kw = x².

x = [H⁺] = √2.88·10⁻¹⁴.

[H⁺] = 1.7·10⁻⁷ M.

pH = - log[H⁺].

pH = - log (1.7·10⁻⁷ M) = 6.77.