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24 February, 03:59

When sodium is excited in a flame, two ultraviolet spectral lines at lambda - 372.1 nm and lambda = 376.4 nm respectively are emitted. which wavelength represented photons?

a) higher energy?

b) longer wavelengths?

c) higher frequences?

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  1. 24 February, 04:20
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    The wavelength that represented photons is at lambda = 376.4 nm.

    The wavelength with the higher energy is at lambda - 372.1 nm.

    The longer wavelength is, of course, at lambda 376.4 nm.

    The wavelength with the higher frequency is 376.4 nm.
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