How much energy is needed to heat a 35.5g sample of ice at - 17.5°C to liquid water at

77.3°C

Answer: Q = 6831.8 J

Explanation: To solve for Q we will use the heat capacity formula:

Q = mc∆T, where the specific heat capacity of ice is (c = 2.03 J / g°C).

Q = 35.5 g (2.03 J / g°C) (77.3°C - (-17.5°C))

Q = 72.065 J / °C (94.8 °C)

Q = 6831.8 J