How will you prepare 10mL of 0.050M HCl from a 0.10M solution of HCl

M₁V₁ = M₂V₂

(0.050M) * (10 mL) = (0.10M) * (x)

x = 5 mL

You would take 5 mL of the 0.10 M solution of HCl and add 5 mL of deionized water. Therefore, the total volume will be 10 mL and it will have a molarity of 0.050.