A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of 21.0°C and a pressure of 122.2kPa. What was the original pressure on the container?

Question

Beatrice

Chemistry

13 September, 15:26

A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of 21.0°C and a pressure of 122.2kPa. What was the original pressure on the container?

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Answers (1)

Know the Answer?

Rebekah Knox · Answer 1

108 kPa

Step-by-step explanation:

To solve this problem, we can use the Combined Gas Laws:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ * T₁/T₂ Divide each side by V₁

p₁ = p₂ * V₂/V₁ * T₁/T₂

dа ta:

p₁ = ?; V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the pressure

p₁ = 122.2 kPa * (29.2/34.3) * (304.65/294.15)

= 122.2 kPa * 0.8542 * 1.0357

= 108 kPa