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29 May, 20:50

How many grams of sulfuric acid are produced when 68.1 g of lead (II) sulfate react?

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  1. 29 May, 21:03
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    The chemical reaction to produce sulfuric acid fro lead (ii) sulfate is:

    PbSO4 + SO2 + 2H2O - - > Pb + 2H2SO4

    first convert the mass of PbSO4 to moles

    moles PbSO4 = 68.1 g (1 mol / 303.26 g)

    moles PbSO4 = 0.2246 mol PbSO4

    mass H2SO4 = 0.2246 mol PbSO4 (2 mol H2SO4 / 1 mol PbSO4) (98 g / mol)

    mas H2SO4 = 44 g H2SO4
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