How much heat is it required to melt 160.0g of water at 0°C

53.3 KJ

Explanation:

Data Given:

amount of ice (mass) = 160 gram

heat required to melt ice (Q) = ?

Solution:

Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.

Formula Used

Q = mLf

Q = heat required to melt a substance

m = mass of the substance

Lf = latent heat of fusion

As we know

latent heat of fusion for water (Lf) = 333.4 J/g

So,

put values in above formula

Q = mLf

Q = 160 g x 333.4 J/g

Q = 53344J

convert J to KJ

1000 J = 1 KJ

53344 J = 53344 / 1000 = 53.344 KJ

Q = 53.3 KJ