An expandable container of oxygen gas has a volume of 125 mL and a temperature of 25.0? C. What volume will the gas occupy at 55°C?

137.6 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 125.0 mL, T₁ = 25°C + 273 = 298 K,

V₂ = ? mL, T₂ = 55°C + 273 = 328 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂) / (T₁) = (125.0 mL) (328 K) / (298 K) = 137.6 mL.