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31 August, 16:11

In the reaction mgcl2 + 2koh mg (oh) 2 + 2kcl, if 3 moles mgcl2 are added to 4 moles koh what determines how much mg (oh) 2 is made

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  1. 31 August, 16:37
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    Every mole of MgCl2 reacts with 2 moles of KOH, therefore the 4 moles of KOH will only react with 2 moles of MgCl2, making it the limiting reagent and therefore KOH determines how much Mg (OH) 2 is produced.
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