2H2O2 (aq) - - > O2 (g) + 2H2O (l). If you use 0.20 M of KI instead of 0.10 M of KI, How would this affect: (a) the slopes of your curves, (b) the rates of the reactions, and (c) the numerical value of k for the reaction?

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Robertson

Chemistry

17 October, 23:26

2H2O2 (aq) - - > O2 (g) + 2H2O (l). If you use 0.20 M of KI instead of 0.10 M of KI, How would this affect: (a) the slopes of your curves, (b) the rates of the reactions, and (c) the numerical value of k for the reaction?

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Cassidy Daniel · Answer 1

This very much depends on order in respect to KI

order of Zero, no change, order 1, rate doubles, order 2, rate quadruples. Which is also one way of working out the rate order.

no change onto steeper on curves. (0 thro ...)

k shouldn't change.

Best Answer is (c) the numerical value of k for the reaction