Ask Question
28 August, 09:31

He standard change in gibbs free energy is δg°/' = 7.53 kj/mol. calculate δg for this reaction at 298 k when [dihydroxyacetone phosphate] = 0.100 m and [glyceraldehyde-3-phosphate] = 0.00500 m. the constant r = 8.3145 j / (k·mol)

+4
Answers (1)
  1. 28 August, 09:56
    0
    I dont understand the question
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “He standard change in gibbs free energy is δg°/' = 7.53 kj/mol. calculate δg for this reaction at 298 k when [dihydroxyacetone phosphate] = ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers