What is the mole fraction of Ba (OH) 2 in an aqueous solution that contains 22.8% Ba (OH) 2 by mass?

Question

Asa Gordon

Chemistry

5 August, 02:40

What is the mole fraction of Ba (OH) 2 in an aqueous solution that contains 22.8% Ba (OH) 2 by mass?

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Answers (1)

Know the Answer?

Natalya Huff · Answer 1

0.03

Explanation:

22.8 g Ba (OH) 2 (1 mol Ba (OH) 2 / 171.34 g) = 0.133 mol Ba (OH) 2

77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O

X = molar fraction = mol Ba (OH) 2 / mol total

X = 0.133 / (0.133+4.29) = 0.03