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29 March, 20:57

How many grams of magnesium metal will react completely with 5.2 liters of 4.0 M HCl?

Mg (s) + 2 HCl (aq) - - > MgCl2 (aq) + H2 (g)

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  1. 29 March, 21:04
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    1) Find the number of mols of HCl in 5.2 liters of 4.0M solution:

    n = M*V (L) = 4.0 mol/L * 5.2 L = 20.8 mol

    2) Find the number of mols of Mg that will react with 20.8 mol of HCl, using the coefficients of the balanced equation

    [1mol Mg / 2 mol HCl] * 20.8 mol HCl = 10.4 mol Mg

    3) Transform mol to mass using the atomic mass:

    10.4 mol Mg * 24.3 g/mol = 252.7 g of Mg.
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