What mass of no2 is contained in a 13.0 l tank at 4.58 atm and 385 k?

Assuming that NO2 is an ideal gas, we can use the ideal gas equation to calculate the moles of the gas in the given conditions. We do as follows:

PV = nRT

n = (4.58) (13) / 0.0825 (385)

n = 2 mol NO2

mass = 2 (46.01) = 92.02 g NO2