Determine the calcium carbonate equivalent (CCE) of the following compounds: (amount that has the same neutralizing value as 100 g pure CaCO3) (a) MgO (b) Mg (OH) 2 (c) and CaMg (CO3) 2.

Question

Payton Cooper

Chemistry

11 April, 20:37

Determine the calcium carbonate equivalent (CCE) of the following compounds: (amount that has the same neutralizing value as 100 g pure CaCO3) (a) MgO (b) Mg (OH) 2 (c) and CaMg (CO3) 2.

+5

Answers (1)

Know the Answer?

Cristal Norris · Answer 1

a) 40 g

b) 58 g

c) 184 g

Explanation:

The calcium carbonate equivalent of any compound is calculated by calculating it molar mass.

The molar mass of the compound is the calcium carbonate equivalent as it corresponds to 1 mole of the compound and equals to one mole of calcium carbonate then.

a) MgO

Atomic mass of Mg = 24

Atomic mass of O = 16

Molar mass = CCE = 24+16 = 40 g

b) Mg (OH) ₂

Atomic mass of Mg = 24

Atomic mass of O = 16

Atomic mass of H = 1

Molar mass of Mg (OH) ₂ = CCE = 24 + (2X16) + 2 (X1) = 58g

c) CaMg (CO₃) 2

Atomic mass of Mg = 24

Atomic mass of O = 16

Atomic mass of C = 12

Atomic mass of Ca = 40

Molar mass = CCE = 40 + 24 + (2X12) + (6X16) = 184 g.