A solution was prepared by dissolving 5.76 g of KCl •MgCl2

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Giana Frederick

Chemistry

11 December, 08:43

A solution was prepared by dissolving 5.76 g of KCl •MgCl2

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Nathaly Blake · Answer 1

a) (10.12 g salt) x [ (1 mole salt) / (277.85 g salt) ] x [ (1) / (2.000 L soln) ] = 0.0182 M

b) (0.0182 M) x [ (1 mole Mg2+) / (1 mole salt) ] = 0.0182 M

c) (0.0182 M) x [ (3 moles Cl-) / (1 mole salt) ] = 0.0546 M

d) [ (10.12 g salt) / (2000 mL) ] x 100% = 0.506% (w/v)

e) (0.0546 M Cl-) (25.0 mL soln) = 1.36 mmoles Cl-

f) [ (0.0182 moles K+) / (1.000 L) ] x [ (39.10 g K+) / (1 mole K+) ] x [ (1 L soln) / (1000 g soln) ] x (1x10^6) = 712 ppm