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21 September, 17:35

What volume of a 5.0 M stock solution of NH3 is needed to

make 3.0 L of 1.40 M NH3?_ _mL

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Answers (1)
  1. 21 September, 17:43
    0
    840mL

    Explanation:

    Given parameters:

    Concentration of stock = 5M

    New volume = 3L

    New concentration = 1.40M

    Unknown:

    Volume of stock needed = ?

    Solution:

    A concentrated standard solution which is the stock may become diluted to a lower concentration before using.

    One important thing is that the number of moles of the substance in the solution before and after is the same.

    Therefore;

    C₁ V₁ = C₂ V₂

    where C and V are concentration and volume

    1 and 2 are initial and final states.

    C₁ = concentration of stock

    V₁ = volume of stock

    C₂ = final concentration

    V₂ = final volume

    5 x V₁ = 1.4 x 3

    V₁ = 0.84L

    This gives 840mL
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