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30 May, 14:03

If 2.06 mL of seawater contains about 0.446 moles of gold, how many atoms of gold are in that volume of seawater?

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  1. 30 May, 14:33
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    2.69 x 10²³ atoms

    Explanation:

    Given parameters:

    Volume of sea water = 2.06mL

    number of moles of gold = 0.446moles

    unknown:

    Number of atoms in the sea water

    Solution:

    The mole is a convenient unit of measuring quantities of particles. In a mole we have 6.02 x 10²³particles.

    The mole can be defined as the amount of a substance contained in Avogadro's number of particles which is 6.02 x 10²³particles.

    Here, the particles we want to determine is the number of atoms:

    Number of atoms is given as:

    Number of gold atoms = number of moles of gold x 6.02 x 10²³

    Number of gold atoms = 0.446 x 6.02 x 10²³ = 2.69 x 10²³ atoms
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