If 2.06 mL of seawater contains about 0.446 moles of gold, how many atoms of gold are in that volume of seawater?

2.69 x 10²³ atoms

Explanation:

Given parameters:

Volume of sea water = 2.06mL

number of moles of gold = 0.446moles

unknown:

Number of atoms in the sea water

Solution:

The mole is a convenient unit of measuring quantities of particles. In a mole we have 6.02 x 10²³particles.

The mole can be defined as the amount of a substance contained in Avogadro's number of particles which is 6.02 x 10²³particles.

Here, the particles we want to determine is the number of atoms:

Number of atoms is given as:

Number of gold atoms = number of moles of gold x 6.02 x 10²³

Number of gold atoms = 0.446 x 6.02 x 10²³ = 2.69 x 10²³ atoms