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16 March, 13:22

What is the [OH-] in a solution with a pOH of 4.22? 1.7 x 10-10 M 6.0 x 10-5 M 6.3 x 10-1 M 1.7 x 104 M

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  1. 16 March, 13:29
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    POH=4.22

    pOH = - lg[OH⁻]

    [OH⁻]=10^ (-pOH)

    [OH⁻]=10⁻⁴·²² = 6.0*10⁻⁵ mol/L

    6.0*10⁻⁵ M
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