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31 March, 02:41

How many grams of lithium are needed to produce 45.0 grams of lithium nitride, according to the following process?

6 Li (s) + N2 (g) → 2 Li2N (s)

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  1. 31 March, 03:01
    0
    33.41 g of Li

    Solution:

    The Balanced Chemical equation is,

    6 Li (s) + N₂ (g) → 2 Li₂ N (s)

    According to equation,

    55.76 g (2 mole) Li ₂N is produced from = 41.4 g (6 mole) Li

    So,

    45 g of Li₂N will be produced from = X g of Li

    Solving for X,

    X = (45 g * 41.4 g) : 55.76 g

    X = 33.41 g of Li
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