A balloon contains 0.76 mol n2, 0.18 mol o2, 0.031 mol he and 0.026 mol h2 at 749 mm hg. what is the partial pressure (in mm hg) of o2? give a numeric answer only, no units.

Question

Kameron Conner

Chemistry

15 June, 04:19

A balloon contains 0.76 mol n2, 0.18 mol o2, 0.031 mol he and 0.026 mol h2 at 749 mm hg. what is the partial pressure (in mm hg) of o2? give a numeric answer only, no units.

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Answers (1)

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Ahmed Rosario · Answer 1

To keep simplicity, let's assume these gases behave ideally so we can use the equations for ideal gas. One of these equation is the Raoult's Law written below.

P * = xP

This is another form of the Raoult's Law where x is the mole fraction. Let's find x for O2.

x = 0.18 / (0.76+0.18+0.031+0.026) = 0.1805

Partial Pressure = (0.1805) (749 mmHg) = 135.23 mmHg