What is the molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water?

1 litre of water is equal to 1000.0 g of water

we need to find molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na: 2 x 22.99 = 45.98

S: 32.07

O: 4 x 16 = 64

Total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 M