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25 July, 20:27

For the reaction represented by the equation 2hno3 + mg (oh) 2® mg (no3) 2 + 2h2o, how many grams of magnesium nitrate are produced from 8.00 mol of nitric acid, hno3, and an excess of mg (oh) 2?

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  1. 25 July, 20:28
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    From the equation 8 mole of Nitric acid produces 4 mole of magnesium nitrate.

    No of moles = mass / molar mass

    Molar mass of magnesium nitrate = 24.3 + 2 (14 + (16*3)) = 24.3 + 2 (14 + 48) = 148.3

    Mass of magnesium nitrate = 4 * 148.3 = 593.2g
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