A 50. g sample of dry iron (II) sulfate has which mass if converted to the pentahydrate?

Question

Katelyn Harmon

Chemistry

29 September, 22:21

A 50. g sample of dry iron (II) sulfate has which mass if converted to the pentahydrate?

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Answers (1)

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Dillon Ruiz · Answer 1

Answer is: mass of iron (II) sulfate pentahydrate (FeSO₄ · 5H₂O) would be 79,62 g.

m (FeSO₄) = 50,0 g.

m (FeSO₄ · 5H₂O) = ?

m (FeSO₄) : M (FeSO₄) = m (FeSO₄ · 5H₂O) : M (FeSO₄ · 5H₂O).

50 g : 151,9 g/mol = m (FeSO₄ · 5H₂O) : 241,9 g/mol.

m (FeSO₄ · 5H₂O) = 50 g · 241,9 g/mol : 151,9 g/mol.

m (FeSO₄ · 5H₂O) = 79,62 g.

M - molar mass.