while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density of aluminum is 2.70 g/cm^3. The accepted value for density of aluminum is 2.70 g/cm^3. What was the student's percent error?

Question

Andy Bonilla

Chemistry

8 June, 13:26

while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density of aluminum is 2.70 g/cm^3. The accepted value for density of aluminum is 2.70 g/cm^3. What was the student's percent error?

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Answers (1)

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Ishaan Alvarez · Answer 1

Percent error = 5.6%

Explanation:

Given dа ta:

Measured value of density by students = 2.85 g/cm³

Accepted density of aluminium = 2.70 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [ Measured value - accepted value / accepted value ] * 100

Now we will put the values in formula:

Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ] * 100

Percent error = [0.15/2.70 g/cm³ ] * 100

Percent error = 0.056 * 100

Percent error = 5.6%