Ask Question
7 September, 00:15

A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm pressure. Calculate the temperature of the helium

+3
Answers (1)
  1. 7 September, 00:21
    0
    299.14 K or 26°C

    Explanation:

    The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.

    The ideal gas law is often written as

    PV = nRT

    where P, V and T are the pressure, volume and absolute temperature;

    n is the number of moles of gas and R is the ideal gas constant.

    n=1.10 x 10^5 mol

    V = 2.70 x 10^6 L

    P = 1.00 atm = 101.325 kPa

    R = 8.314 kPa*L / mol*K

    when the formula is rearranged, T=PV / nR

    T = (101.325kPa * 2.70 x 10^6 L) / (1.10 x 10^5 mol * 8.314 kPa*L / mol*K)

    T = 299.1421917 K

    or

    T = 299.14 - 273.15 = 25.99 = 26°C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm pressure. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers