Calculate the {H+}, {OH-}, oh, pOH, and % dissociation of a 1.0x10^-3 M solution of HCl

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Bianca

Chemistry

15 April, 08:56

Calculate the {H+}, {OH-}, oh, pOH, and % dissociation of a 1.0x10^-3 M solution of HCl

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Meyer · Answer 1

Since HCl is a strong acid, it readily dissociates, so we can assume that there are 1.0x10^-3 M of H + ions. We can use the formula:

pH=-log[H+]

pH=-log (1.0x10^-3)

pH=3

We can find the pOH by subtracting 14-pH:

14-3=11

pOH=11

The [OH-] can be found by using the formula:

pOH=-log[OH-]

11=-log[OH-]

10^-11=[OH-]

[OH-]=1.0x10^-10