A chemist dissolves 660. mg of pure hydroiodic acid in enough water to make up 300. mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

Question

Lamar Shields

Chemistry

19 June, 05:28

A chemist dissolves 660. mg of pure hydroiodic acid in enough water to make up 300. mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

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Answers (1)

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Ciara Hutchinson · Answer 1

660mg = 0.660g

300mL = 0.300L

0.660g/0.300L = 2.2M

ICE Box

HI + H2O - -> H3O + I-

I. 2.2M 0M 0M

C - x + x + x

E 2.2M x x

You would need k to find x using the equation k = [H3O][I-]/[HI]. To find the pH, use the equation pH = - log[H3O].