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21 February, 03:20

1. Using the balanced equation, answer the following questions:

2KClO3 → 2KCl + 3O2

a. How many molecules of O2 will be formed from 34.35 grams of KClO3?

b. How many grams of KCl will be formed from 52.53 grams of KClO3?

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Answers (1)
  1. 21 February, 04:54
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    a) 2.53 * 10²³ molecules of O₂

    b) 31.90 g of KCl

    Explanation:

    The balance chemical equation for given decomposition reaction is as follow;

    2 KClO₃ → 2 KCl + 3 O₂

    Part 1:

    Step 1: Calculate Moles for given amount of KClO₃;

    Moles = Mass / M. Mass

    Moles = 34.35 g / 122.55 g/mol

    Moles = 0.280 moles of KClO₃

    Step 2: Find out moles of O₂ produced;

    According to eq,

    2 moles of KClO₃ produces = 3 moles of O₂

    So,

    0.280 moles of KClO₃ will produce = X moles of O₂

    Solving for X,

    X = 0.280 mol * 3 mol / 2 mol

    X = 0.42 moles of O₂

    Step 3: Calculate No. of Molecules of O₂ as,

    No. of Molecules = Moles * 6.022 * 10²³

    No. of Molecules = 0.42 mol * 6.022 * 10²³ molecules/mol

    No. of Molecules = 2.53 * 10²³ molecules of O₂

    Part 2:

    Step 1: Calculate Moles for given amount of KClO₃;

    Moles = Mass / M. Mass

    Moles = 52.53 g / 122.55 g/mol

    Moles = 0.428 moles of KClO₃

    Step 2: Find out moles of KCl produced;

    According to eq,

    2 moles of KClO₃ produces = 2 moles of KCl

    So,

    0.428 moles of KClO₃ will produce = X moles of KCl

    Solving for X,

    X = 0.428 mol * 2 mol / 2 mol

    X = 0.428 moles of KCl

    Step 3: Calculate Mass of KCl as;

    Mass = Moles * M. Mass

    Mass = 0.428 mol * 74.55 g/mol

    Mass = 31.90 g of KCl
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