Sodium and water react according to the following equation. If 51.5 g of sodium are added to access water, how many liters of hydrogen gas are formed the STP? Show all work.

2Na+2H2O->2NaOH+H2

Answer is: volume is 25.08 liters.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂ (g).

m (Na) = 51.5 g; mass of sodium.

n (Na) = m (Na) : M (Na).

n (Na) = 51.5 g : 23 g/mol.

n (Na) = 2.24 mol; amount of sodium.

From chemical reaction: n (Na) : n (H₂) = 2 : 1.

n (H₂) = 2.24 mol : 2.

m (H₂) = 1.12 mol; amount of hydrogen gas.

V (H₂) = n (H₂) · Vm.

V (H₂) = 1.12 mol · 22.4 L/mol.

V (H₂) = 25.08 L; volume of hydrogen gas.