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18 February, 14:24

What is the osmotic pressure of a solution made by dissolving 75.0 g of glucose, c6h12o6, in enough water to form 700.0 ml of solution at 45.0 ∘c? express your answer to three significant figures and include the appropriate u?

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  1. 18 February, 14:46
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    We will use the osmotic pressure formula:

    π = n R T / V

    When π is the osmotic pressure (atm)

    n is no. of moles when the molar mass of glucose = 180 g/mol

    so, n = 75 g / 180 g/mol = 0.42

    and R is gas constant = 0.0821 L. atm/mol. k

    T is the temperature in Kelvin = 45 + 273 = 318 K

    and V is the volume in Litre = 700 / 1000 = 0.7 L

    So, by substitution:

    ∴ π = 0.42 * 0.0821 * 318 / 0.7 = 15.665 atm
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