What is the osmotic pressure of a solution made by dissolving 75.0 g of glucose, c6h12o6, in enough water to form 700.0 ml of solution at 45.0 ∘c? express your answer to three significant figures and include the appropriate u?

We will use the osmotic pressure formula:

π = n R T / V

When π is the osmotic pressure (atm)

n is no. of moles when the molar mass of glucose = 180 g/mol

so, n = 75 g / 180 g/mol = 0.42

and R is gas constant = 0.0821 L. atm/mol. k

T is the temperature in Kelvin = 45 + 273 = 318 K

and V is the volume in Litre = 700 / 1000 = 0.7 L

So, by substitution:

∴ π = 0.42 * 0.0821 * 318 / 0.7 = 15.665 atm