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12 July, 02:28

After 43.0 minutes, 34.0% of compound decomposed. What is the half-life of this reaction assuming first order kinetics?

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  1. 12 July, 02:33
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    34% decomposition means that 66% of the compound remained, meaning the ratio of current to initial concentration after 43 minutes was 0.66. The decomposition equation:

    ln[A] = ln[Ao] - kt

    ln ([A] / [Ao]) = - kt

    Now, we substitute the given values:

    ln (0.66) = - k (43)

    k = 9.66 x 10⁻³

    half life = ln (2) / k

    half life = 71.8 minutes.
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