What is the molarity of an h3po4 solution if 15.0 ml is completely neutralized by 38.5 ml of 0.150m naoh?

Question

Ivan Leach

Chemistry

30 January, 15:15

What is the molarity of an h3po4 solution if 15.0 ml is completely neutralized by 38.5 ml of 0.150m naoh?

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Alan Murillo · Answer 1

The molarity of H3PO4 solution if 15.0 ml is completely neutralized by 38.5 ml of 0.15m naoh is calculated as follows

find moles of NaOH used = molarity x volume

= 38.5 x 0.15 = 5.775 moles

write the reacting equation

3NaOH + H3PO4 = Na3PO4 + 3H2O

from the equation the reacting ratio between NaOH to H3Po4 which is 3:1 the moles of H3PO4 is therefore = 5.775/3 = 1.925 moles

molarity of H3PO4 is therefore = moles / volume

= 1.925/15 = 0.128 M