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30 March, 07:21

If 1.00L of muriatic acid w / a pH of 2.5 is poured to 8.00L water, what is the new molar concentration of the muriatic solution? Hint: use C1•V1 = C2•V2

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  1. 30 March, 07:30
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    The answer to your question is: C2 = 0.0004 M

    Explanation:

    Data

    pH = 2.5; V = 1.0 L

    V2 = 8.0 L C2 = ?

    Formula

    C1V1 = C2V2

    C2 = C1V1 / V2

    pH = - log[H⁺]

    Process

    [H⁺] = antilog - pH

    [H⁺] = antilog (-2.5)

    [H⁺] = 0.003 M = C1

    Finally

    (0.003) (1 l) = C2 (8)

    C2 = 0.003 / 8

    C2 = 0.0004 M
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