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21 September, 00:14

How many grams of CO2could be produced from the combustion of 23g of C4H10in the presence of an adequate amount of O2?

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  1. 21 September, 00:32
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    Mass = 70.4 g

    Explanation:

    Given dа ta:

    Mass of CO₂ produced = ?

    Mass of C₄H₁₀ = 23 g

    Solution:

    Chemical equation:

    2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

    Number of moles of C₄H₁₀:

    Number of moles = mass / molar mass

    Number of moles = 23 g / 58.12 g/mol

    Number of moles = 0.4 mol

    Now we will compare the moles of C₄H₁₀ and CO₂ from balance chemical equation.

    C₄H₁₀ : CO₂

    2 : 8

    0.4 : 8/2*0.4 = 1.6 mol

    Mass of CO₂:

    Mass = number of moles * molar mass

    Mass = 1.6 mol * 44 g/mol

    Mass = 70.4 g
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